¿ìè¶ÌÊÓÆµ

Solution to Enigma No. 1577

Figure 1
Figure 1

Answer: The three numbers are 325, 784 and 901

The winner is Jeremy Gray from Epsom, Auckland, New Zealand. There were 210 entries.

Worked answer

The sum of the 9 digits used must be between 36 (if 9 is not used) and 45 (if 0 is not used).

So the sum of the digits used in each column must be:

  • Hundreds: 20 (less carry from tens)
  • Tens: 11 (less carry from units)
  • Units: 10

This means that the sums must be: H 19, T 10, U 10; and the unused digit is 6.

19 can be achieved in 3 ways: 9+8+2, 9+7+3, 8+7+4.

10 can be achieved in 6 ways: 9+1+0, 8+2+0, 7+3+0, 7+2+1, 5+4+1, 5+3+2.

Since the tens and units are interchangeable there are 6 possible combinations: see figure 1, right.

Since squares do not end in 2, 3, 7 or 8 and those that end in 0 or 5 always end in 00 or 25, (b), (d) and (e) cannot furnish a perfect square.

We can omit squares that start with 1 or 5 or contain a 6 or a repeated digit, leaving 289 (impossible), 324 (c), 729 (f), 784 (c) and 841 (impossible).

If 324 (c), the other numbers are: 985 and 701, or 905 and 781, or 981 and 705, or 901 and 785.

If 729 (f), the other numbers are: 851 and 430, or 831 and 450, or 850 and 431, or 830 and 451.

If 784 (c), the other numbers are: 925 and 301, or 905 and 321, or 921 and 305, or 901 and 325.

Triangular numbers that start with 3, 4, 7, 8 or 9 and contain neither a 6 nor a repeated digit are 325, 351, 378, 435, 703, 741, 780, 820 and 903.

So 325 is the only triangular number that can be used, along with 784 and 901.

More from ¿ìè¶ÌÊÓÆµ

Explore the latest news, articles and features